To evaluate the integral of ( \frac{\ln(x)}{x^2} ), we can utilize the method of integration by parts. The integral can be expressed as follows:
∫x2ln(x)dxWe choose our variables for integration by parts:
Applying the integration by parts formula, which is given by
∫udv=uv−∫vdu,we can substitute our choices into the formula:
∫x2ln(x)dx=−xln(x)−∫−x1dx.The integral ( \int -\frac{1}{x} , dx ) can be evaluated using the standard rule for the integral of ( \frac{1}{x} ):
∫−x1dx=−ln(x)+C.Now substituting this back into our previous expression, we have:
∫x2ln(x)dx=−xln(x)+ln(x)+C.Next, we can simplify the expression:
∫x2ln(x)dx=−x1+xln(x)+C.Thus, the final result for the integral is:
∫x2ln(x)dx=−x1+xln(x)+C.In summary, the integral of ( \frac{\ln(x)}{x^2} ) is:
−x1+xln(x)+C.![]() 100% | ![]() Global | ![]() 97% | |
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