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What's the integral of e^(2x)?

Here’s an enhanced version of your content for clarity and readability:

The integral of e2xe^{2x} can be expressed as

e2xdx=12e2x+C\int e^{2x} \, dx = \frac{1}{2} e^{2x} + C

where CC represents the constant of integration.

To compute the integral of e2xe^{2x}, we typically rely on the power rule of integration, which states that

xndx=1n+1xn+1+C\int x^n \, dx = \frac{1}{n+1} x^{n+1} + C

However, since e2xe^{2x} does not match the form xnx^n, we will employ a different technique: substitution.

We can let u=2xu = 2x. Then, we differentiate to find dudx=2\frac{du}{dx} = 2, which implies that

dx=12du.dx = \frac{1}{2} \, du.

By substituting these into the integral, we have:

e2xdx=eu(12du)=12eudu=12eu+C=12e2x+C.\int e^{2x} \, dx = \int e^u \left( \frac{1}{2} \, du \right) = \frac{1}{2} \int e^u \, du = \frac{1}{2} e^u + C = \frac{1}{2} e^{2x} + C.

In summary, to find the integral of e2xe^{2x}, we perform a substitution by letting u=2xu = 2x. This transforms the integral into

12eudu,\frac{1}{2} \int e^u \, du,

which is straightforward to evaluate. The final result is

12e2x+C,\frac{1}{2} e^{2x} + C,

where CC is a constant of integration. This method illustrates how substitution can effectively simplify and solve integrals that do not conform to standard forms.

Answered by: Dr. Michael Green
A-Level Maths Tutor
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