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What is the unit vector in the direction of (7, 24)?

The unit vector in the direction of the vector (7,24)(7, 24) is given by (725,2425)\left( \frac{7}{25}, \frac{24}{25} \right).

To calculate the unit vector corresponding to a given vector, we first need to determine the magnitude (or length) of that vector. The magnitude of a vector represented as (a,b)(a, b) can be calculated using the formula:

Magnitude=a2+b2\text{Magnitude} = \sqrt{a^2 + b^2}

For the vector (7,24)(7, 24), we substitute the components into the formula:

Magnitude=72+242=49+576=625=25\text{Magnitude} = \sqrt{7^2 + 24^2} = \sqrt{49 + 576} = \sqrt{625} = 25

Once we have the magnitude, we can obtain the unit vector by dividing each component of the original vector by its magnitude. This process normalizes the vector, resulting in a vector of length 1 while preserving its direction. The unit vector u\mathbf{u} can be expressed as:

u=(725,2425)\mathbf{u} = \left( \frac{7}{25}, \frac{24}{25} \right)

Thus, the unit vector in the direction of (7,24)(7, 24) is:

(725,2425)\left( \frac{7}{25}, \frac{24}{25} \right)

This implies that if you visualize the vector (7,24)(7, 24) and then scale it down so that its length becomes exactly 11, the resulting vector will have components 725\frac{7}{25} and 2425\frac{24}{25}. This unit vector points in the same direction as the original vector but has a standardized length. It is particularly useful in various applications within mathematics and physics, such as defining directions independently of magnitude.

Answered by: Prof. Peter Brown
IB Maths Tutor
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