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What is the pattern in the sequence 2, 4, 8, 16?

The sequence 2,4,8,162, 4, 8, 16 illustrates a clear pattern: each term is double the preceding term.

This sequence represents a geometric progression, where each term is generated by multiplying the previous term by a constant factor. In this case, the constant factor is 22. Starting with the first term, 22, we multiply by 22 to obtain the second term, 44. Continuing this process, we multiply 44 by 22 to arrive at the third term, 88, and so forth. This doubling pattern continues indefinitely, with each term consistently being twice the value of its predecessor.

To delve deeper into this progression, let’s denote the first term of the sequence as aa. Here, we have a=2a = 2. The common ratio, which is the factor used to obtain each successive term, is r=2r = 2. The general formula for the nn-th term of a geometric sequence is given by

a×r(n1).a \times r^{(n-1)}.

For this specific sequence, the nn-th term can be expressed as

2×2(n1).2 \times 2^{(n-1)}.

For example, to calculate the 4th term:

2×2(41)=2×23=2×8=16.2 \times 2^{(4-1)} = 2 \times 2^3 = 2 \times 8 = 16.

Understanding this pattern enables us to predict future terms of the sequence without listing all the preceding terms. For instance, the 5th term can be calculated as follows:

2×2(51)=2×24=2×16=32.2 \times 2^{(5-1)} = 2 \times 2^4 = 2 \times 16 = 32.

Utilizing the general formula is especially advantageous for sequences with a large number of terms, as it allows for quick calculations and predictions.

Answered by: Dr. Sarah Wilson
GCSE Physics Tutor
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