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What is the gradient of the line passing through (1, 4) and (3, 10)?

The gradient of the line that passes through the points (1,4)(1, 4) and (3,10)(3, 10) is equal to 33.

To determine the gradient of a line, we utilize the formula:

Gradient=change in ychange in x\text{Gradient} = \frac{\text{change in } y}{\text{change in } x}

This formula allows us to assess the steepness of the line by comparing the vertical change (often referred to as “rise”) to the horizontal change (known as “run”) between two points on the line.

Let’s apply this formula to the specified points (1,4)(1, 4) and (3,10)(3, 10). We start by identifying the coordinates: the first point, denoted as (x1,y1)(x_1, y_1), is (1,4)(1, 4), and the second point, denoted as (x2,y2)(x_2, y_2), is (3,10)(3, 10).

Next, we calculate the change in yy (the vertical change) and the change in xx (the horizontal change):

Change in y=y2y1=104=6\text{Change in } y = y_2 - y_1 = 10 - 4 = 6 Change in x=x2x1=31=2\text{Change in } x = x_2 - x_1 = 3 - 1 = 2

Now, we substitute these values into the gradient formula:

Gradient=change in ychange in x=62=3\text{Gradient} = \frac{\text{change in } y}{\text{change in } x} = \frac{6}{2} = 3

Thus, the gradient of the line that passes through the points (1,4)(1, 4) and (3,10)(3, 10) is 33. This indicates that for every unit you move horizontally to the right along the line, the line ascends vertically by 33 units. Understanding the gradient is essential for analyzing the steepness and direction of a line in a graph.

Answered by: Dr. Angela Davis
GCSE Maths Tutor
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