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What is the distance between (1, 2) and (4, 6)?

The distance between the points (1,2)(1, 2) and (4,6)(4, 6) is 55 units.

To calculate the distance between two points on a coordinate plane, we utilize the distance formula, which is derived from the Pythagorean theorem. The distance formula is expressed as:

Distance=(x2x1)2+(y2y1)2\text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

In this formula, (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) represent the coordinates of the two points. For our specific points, we assign (x1,y1)=(1,2)(x_1, y_1) = (1, 2) and (x2,y2)=(4,6)(x_2, y_2) = (4, 6).

First, we calculate the differences in the x-coordinates and y-coordinates as follows:

x2x1=41=3x_2 - x_1 = 4 - 1 = 3 y2y1=62=4y_2 - y_1 = 6 - 2 = 4

Next, we square these differences:

(x2x1)2=32=9(x_2 - x_1)^2 = 3^2 = 9 (y2y1)2=42=16(y_2 - y_1)^2 = 4^2 = 16

We then sum these squared differences:

9+16=259 + 16 = 25

Finally, we take the square root of this result to determine the distance:

25=5\sqrt{25} = 5

Thus, the distance between the points (1,2)(1, 2) and (4,6)(4, 6) is indeed 55 units. This method can be applied to any pair of points on a coordinate plane, making it an invaluable tool in geometry.

Answered by: Prof. Michael Lewis
IB Physics Tutor
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