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What is the actual length if the scale is 1;10 and the drawing length is 5 cm?

The actual length of an object is 50cm50 \, \text{cm} when using a scale of 1:101:10, and the corresponding drawing length is 5cm5 \, \text{cm}.

When working with scales, it is essential to recognize that they represent a ratio between the dimensions depicted in a drawing and the actual dimensions of the object. In this example, the scale of 1:101:10 indicates that 11 unit on the drawing corresponds to 1010 units in real life. To determine the actual length of an object, you multiply the drawing length by the scale factor.

In this case, the drawing length is 5cm5 \, \text{cm}. By applying the scale factor of 1010, you calculate the actual length as follows:

Actual Length=Drawing Length×Scale Factor=5cm×10=50cm.\text{Actual Length} = \text{Drawing Length} \times \text{Scale Factor} = 5 \, \text{cm} \times 10 = 50 \, \text{cm}.

Thus, if an object measures 5cm5 \, \text{cm} in the drawing, its real-life length would be 50cm50 \, \text{cm}.

Understanding scales is vital in various fields, including architecture, engineering, and geography, where precise representations of objects and distances are crucial. By mastering the use and interpretation of scales, you can ensure that your measurements and drawings are both accurate and practical.

Answered by: Dr. Sarah Wilson
GCSE Physics Tutor
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