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What does the graph of y = -2^x look like?

The graph of the function y=2xy = -2^x represents a downward-sloping exponential curve that approaches zero but never intersects it.

To elaborate, the equation y=2xy = -2^x exemplifies an exponential function characterized by a negative coefficient. This implies that as the value of xx increases, the value of yy decreases exponentially. The base of the exponent is 2, indicating that the function decays at a rate proportional to powers of 2. However, due to the negative sign preceding 2x2^x, the graph is reflected across the x-axis relative to the graph of y=2xy = 2^x.

When x=0x = 0, we find that y=20=1y = -2^0 = -1. This gives us the y-intercept at the coordinate point (0,1)(0, -1). As xx takes on positive values, yy rapidly becomes more negative. For instance, when x=1x = 1, y=21=2y = -2^1 = -2, and when x=2x = 2, y=22=4y = -2^2 = -4. This demonstrates that the graph descends steeply as xx increases.

In contrast, when xx takes on negative values, yy approaches zero from the negative side. For example, when x=1x = -1, we have y=21=12y = -2^{-1} = -\frac{1}{2}, and when x=2x = -2, y=22=14y = -2^{-2} = -\frac{1}{4}. This behavior indicates that the graph gets increasingly closer to the x-axis without ever touching it, thereby establishing a horizontal asymptote at y=0y = 0.

In summary, the graph of y=2xy = -2^x is a steep, downward-sloping curve that begins at y=1y = -1 when x=0x = 0 and decreases rapidly as xx increases, while it approaches zero as xx decreases.

Answered by: Dr. Emily Clark
GCSE Maths Tutor
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