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What does a high Kc value indicate?

A high equilibrium constant, denoted as KcK_c, indicates that the equilibrium position favors the formation of products, suggesting that the reaction is likely to proceed nearly to completion.

In the realm of chemical equilibrium, the equilibrium constant KcK_c quantifies the ratio of the concentrations of products to those of reactants at equilibrium. A high KcK_c value signifies that the concentration of products is significantly greater than that of the reactants, implying that most of the reactants have been converted into products.

The equilibrium constant is derived from the law of mass action, which states that the rate of a chemical reaction is directly proportional to the product of the concentrations of the reactants. For a balanced chemical equation, the expression for the equilibrium constant is formulated as the product of the concentrations of the products, each raised to their respective stoichiometric coefficients, divided by the product of the concentrations of the reactants, each also raised to their respective coefficients.

For instance, consider a general reaction represented as:

aA+bBcC+dDaA + bB \rightleftharpoons cC + dD

The expression for the equilibrium constant KcK_c is given by:

Kc=[C]c[D]d[A]a[B]bK_c = \frac{[C]^c [D]^d}{[A]^a [B]^b}

In this expression, square brackets denote the concentrations of the substances involved, while the letters aa, bb, cc, and dd represent the stoichiometric coefficients from the balanced equation.

When KcK_c is much greater than 1, it indicates that the numerator (the product of the concentrations of the products) is considerably larger than the denominator (the product of the concentrations of the reactants). This suggests that, at equilibrium, the mixture predominantly consists of products, reinforcing the notion that the reaction tends to proceed to completion.

It is important to note that the value of KcK_c is dependent on temperature. Changes in temperature will affect the rates of the forward and reverse reactions, consequently altering the equilibrium position and thus the value of KcK_c.

Answered by: Prof. Matthew Carter
GCSE Chemistry Tutor
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