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Solve the equation ln(2x) = 4

Here is an enhanced version of your content for clarity and readability:

The solution to the equation ln(2x)=4\ln(2x) = 4 is given by x=e42x = \frac{e^4}{2}.

To solve the equation ln(2x)=4\ln(2x) = 4, we first need to isolate the variable xx. We accomplish this by exponentiating both sides of the equation with the base ee, which is the base of the natural logarithm. This results in the following equation:

eln(2x)=e4e^{\ln(2x)} = e^4

Utilizing the property of logarithms that states ln(ea)=a\ln(e^a) = a, we can simplify the left-hand side:

2x=e42x = e^4

Next, we isolate xx by dividing both sides of the equation by 2:

x=e42x = \frac{e^4}{2}

This expression can also be rewritten as:

x=e2e212x = e^{2} \cdot e^{2} \cdot \frac{1}{2}

However, it is more straightforward to present it as:

x=e42x = \frac{e^4}{2}

Thus, the final solution to the equation ln(2x)=4\ln(2x) = 4 is:

x=e42x = \frac{e^4}{2}.

Answered by: Prof. Isabella Taylor
A-Level Maths Tutor
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