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How to integrate sec^2(x)?

To integrate the function sec2(x)\sec^2(x), we can use the established formula:

sec2(x)dx=tan(x)+C\int \sec^2(x) \, dx = \tan(x) + C

where CC represents the constant of integration.

To understand this formula, we start with the derivative of tan(x)\tan(x):

ddxtan(x)=sec2(x)\frac{d}{dx} \tan(x) = \sec^2(x)

By integrating both sides with respect to xx, we arrive at:

sec2(x)dx=tan(x)+C\int \sec^2(x) \, dx = \tan(x) + C

Thus, to find the integral of sec2(x)\sec^2(x), simply apply the formula and include the constant of integration:

sec2(x)dx=tan(x)+C\int \sec^2(x) \, dx = \tan(x) + C

For instance, if we want to compute the integral of sec2(3x)\sec^2(3x), we can use the formula as follows:

sec2(3x)dx=tan(3x)+C\int \sec^2(3x) \, dx = \tan(3x) + C

It’s important to note that this formula specifically applies to sec2(x)\sec^2(x) and does not extend to other powers of sec(x)\sec(x). For integrating different powers of sec(x)\sec(x), alternative techniques must be employed.

Answered by: Prof. Peter Brown
IB Maths Tutor
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