To compute the integral of the function exsin(x)ln(x), we will apply the method of integration by parts. We start by choosing u=ln(x) and dv=exsin(x)dx.
Applying integration by parts, we have:
∫exsin(x)ln(x)dx=ln(x)(−excos(x))−∫−excos(x)dx.This simplifies to:
∫exsin(x)ln(x)dx=−excos(x)ln(x)+∫excos(x)dx.Next, we will apply integration by parts again to the integral ∫excos(x)dx. This time, we set u=cos(x) and dv=exdx:
∫excos(x)dx=cos(x)ex−∫−exsin(x)dx.Substituting this back gives us:
∫exsin(x)ln(x)dx=−excos(x)ln(x)+(excos(x)−∫exsin(x)dx).Now, simplifying this expression results in:
∫exsin(x)ln(x)dx=−excos(x)ln(x)+excos(x)−∫exsin(x)dx.Next, we will perform integration by parts one more time on the integral ∫exsin(x)dx, with u=sin(x) and dv=exdx:
∫exsin(x)dx=sin(x)ex−∫excos(x)dx.Substituting this back into our earlier expression gives us:
∫exsin(x)ln(x)dx=−excos(x)ln(x)+excos(x)−(sin(x)ex−∫excos(x)dx).After simplifying, we arrive at:
∫exsin(x)ln(x)dx=ex(−cos(x)ln(x)+sin(x)−cos(x))+C,where C is the constant of integration.
Thus, we conclude that the integral of exsin(x)ln(x) is given by:
∫exsin(x)ln(x)dx=ex(−cos(x)ln(x)+sin(x)−cos(x))+C.![]() 100% | ![]() Global | ![]() 97% | |
---|---|---|---|
Professional Tutors | International Tuition | Independent School Entrance Success | |
All of our elite tutors are full-time professionals, with at least five years of tuition experience and over 5000 accrued teaching hours in their subject. | Based in Cambridge, with operations spanning the globe, we can provide our services to support your family anywhere. | Our families consistently gain offers from at least one of their target schools, including Eton, Harrow, Wellington and Wycombe Abbey. |
![]() 100% |
---|
Professional Tutors |
All of our elite tutors are full-time professionals, with at least five years of tuition experience and over 5000 accrued teaching hours in their subject. |
![]() Global |
International Tuition |
Based in Cambridge, with operations spanning the globe, we can provide our services to support your family anywhere. |
![]() 97% |
Independent School Entrance Success |
Our families consistently gain offers from at least one of their target schools, including Eton, Harrow, Wellington and Wycombe Abbey. |
At the Beyond Tutors we recognise that no two students are the same.
That’s why we’ve transcended the traditional online tutoring model of cookie-cutter solutions to intricate educational problems. Instead, we devise a bespoke tutoring plan for each individual student, to support you on your path to academic success.
To help us understand your unique educational needs, we provide a free 30-minute consultation with one of our founding partners, so we can devise the tutoring plan that’s right for you.
To ensure we can best prepare for this consultation, we ask you to fill out the short form below.