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How to integrate e^x*sin(x)*ln(x)?

To compute the integral of the function exsin(x)ln(x)e^x \sin(x) \ln(x), we will apply the method of integration by parts. We start by choosing u=ln(x)u = \ln(x) and dv=exsin(x)dxdv = e^x \sin(x) \, dx.

Applying integration by parts, we have:

exsin(x)ln(x)dx=ln(x)(excos(x))excos(x)dx.\int e^x \sin(x) \ln(x) \, dx = \ln(x) \left(-e^x \cos(x)\right) - \int -e^x \cos(x) \, dx.

This simplifies to:

exsin(x)ln(x)dx=excos(x)ln(x)+excos(x)dx.\int e^x \sin(x) \ln(x) \, dx = -e^x \cos(x) \ln(x) + \int e^x \cos(x) \, dx.

Next, we will apply integration by parts again to the integral excos(x)dx\int e^x \cos(x) \, dx. This time, we set u=cos(x)u = \cos(x) and dv=exdxdv = e^x \, dx:

excos(x)dx=cos(x)exexsin(x)dx.\int e^x \cos(x) \, dx = \cos(x) e^x - \int -e^x \sin(x) \, dx.

Substituting this back gives us:

exsin(x)ln(x)dx=excos(x)ln(x)+(excos(x)exsin(x)dx).\int e^x \sin(x) \ln(x) \, dx = -e^x \cos(x) \ln(x) + \left( e^x \cos(x) - \int e^x \sin(x) \, dx \right).

Now, simplifying this expression results in:

exsin(x)ln(x)dx=excos(x)ln(x)+excos(x)exsin(x)dx.\int e^x \sin(x) \ln(x) \, dx = -e^x \cos(x) \ln(x) + e^x \cos(x) - \int e^x \sin(x) \, dx.

Next, we will perform integration by parts one more time on the integral exsin(x)dx\int e^x \sin(x) \, dx, with u=sin(x)u = \sin(x) and dv=exdxdv = e^x \, dx:

exsin(x)dx=sin(x)exexcos(x)dx.\int e^x \sin(x) \, dx = \sin(x) e^x - \int e^x \cos(x) \, dx.

Substituting this back into our earlier expression gives us:

exsin(x)ln(x)dx=excos(x)ln(x)+excos(x)(sin(x)exexcos(x)dx).\int e^x \sin(x) \ln(x) \, dx = -e^x \cos(x) \ln(x) + e^x \cos(x) - \left( \sin(x) e^x - \int e^x \cos(x) \, dx \right).

After simplifying, we arrive at:

exsin(x)ln(x)dx=ex(cos(x)ln(x)+sin(x)cos(x))+C,\int e^x \sin(x) \ln(x) \, dx = e^x \left(-\cos(x) \ln(x) + \sin(x) - \cos(x)\right) + C,

where CC is the constant of integration.

Thus, we conclude that the integral of exsin(x)ln(x)e^x \sin(x) \ln(x) is given by:

exsin(x)ln(x)dx=ex(cos(x)ln(x)+sin(x)cos(x))+C.\int e^x \sin(x) \ln(x) \, dx = e^x \left(-\cos(x) \ln(x) + \sin(x) - \cos(x)\right) + C.
Answered by: Dr. Daniel Thompson
A-Level Maths Tutor
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