To compute the hyperbolic functions of a complex number, we utilize the definitions of the hyperbolic sine, cosine, and tangent functions.
Let a complex number be defined as:
z=x+iywhere ( x ) and ( y ) are the real and imaginary parts, respectively. The hyperbolic functions of ( z ) are defined as follows:
sinh(z)=2ez−e−z cosh(z)=2ez+e−z tanh(z)=cosh(z)sinh(z)To evaluate these functions, we first express ( e^z ) and ( e^{-z} ) using Euler’s formula:
ez=ex⋅eiy=ex⋅(cos(y)+isin(y)) e−z=e−x⋅e−iy=e−x⋅(cos(y)−isin(y))Now we can substitute these expressions into the definitions of the hyperbolic functions.
Calculating ( \sinh(z) ):
[ \sinh(z) = \frac{e^z - e^{-z}}{2} = \frac{e^x \cdot (\cos(y) + i \sin(y)) - e^{-x} \cdot (\cos(y) - i \sin(y))}{2} ]
This simplifies to:
[ \sinh(z) = \frac{(e^x - e^{-x})}{2} \cos(y) + i \frac{(e^x + e^{-x})}{2} \sin(y) ]
Calculating ( \cosh(z) ):
[ \cosh(z) = \frac{e^z + e^{-z}}{2} = \frac{e^x \cdot (\cos(y) + i \sin(y)) + e^{-x} \cdot (\cos(y) - i \sin(y))}{2} ]
This simplifies to:
[ \cosh(z) = \frac{(e^x + e^{-x})}{2} \cos(y) + i \frac{(e^x - e^{-x})}{2} \sin(y) ]
Calculating ( \tanh(z) ):
Finally, we find ( \tanh(z) ):
[ \tanh(z) = \frac{\sinh(z)}{\cosh(z)} = \frac{\left[ \frac{(e^x - e^{-x})}{2} \cos(y) + i \frac{(e^x + e^{-x})}{2} \sin(y) \right]}{\left[ \frac{(e^x + e^{-x})}{2} \cos(y) + i \frac{(e^x - e^{-x})}{2} \sin(y) \right]} ]
This can be further simplified to:
tanh(z)=cosh(x)sinh(x)+itan(y)In summary, the hyperbolic functions for a complex number ( z = x + iy ) can be expressed in terms of its real and imaginary components, allowing for straightforward calculations in complex analysis.
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