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How do you write the equation of a line with slope 1/2 and y-intercept -2?

The equation of the line can be expressed as

y=12x2.y = \frac{1}{2}x - 2.

To formulate the equation of a line, it is essential to identify two key components: the slope (or gradient) and the y-intercept. The general equation of a line is given by

y=mx+c,y = mx + c,

where mm represents the slope and cc denotes the y-intercept. In this scenario, the slope mm is 12\frac{1}{2} and the y-intercept cc is 2-2.

The slope indicates the steepness of the line. A slope of 12\frac{1}{2} signifies that for every 22 units you move horizontally to the right, the line ascends by 11 unit vertically. The y-intercept indicates the point at which the line intersects the y-axis; here, the line crosses the y-axis at 2-2.

By substituting the given slope and y-intercept into the general form, we arrive at

y=12x2.y = \frac{1}{2}x - 2.

This equation allows you to calculate the corresponding value of yy for any given value of xx by multiplying xx by 12\frac{1}{2} and then subtracting 22. For instance, if we take x=4x = 4, we can find yy as follows:

y=12×42=22=0.y = \frac{1}{2} \times 4 - 2 = 2 - 2 = 0.

This equation is particularly useful for graphing the line or determining specific points along it. It is important to remember that the slope and y-intercept are fundamental elements in understanding the behavior of the line.

Answered by: Prof. Peter Brown
IB Maths Tutor
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