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How do you solve the equation sin(x) = 0 for x in radians?

The solutions to the equation sin(x)=0\sin(x) = 0 are given by the expression x=nπx = n\pi, where nn is any integer.

To solve the equation sin(x)=0\sin(x) = 0, we need to identify the values of xx for which the sine function equals zero. The sine function, denoted as sin(x)\sin(x), is periodic with a period of 2π2\pi, indicating that it repeats its values every 2π2\pi radians. Within each period, the sine function takes the value of zero at specific angles.

In one complete cycle (or period), the sine function equals zero at the points x=0x = 0, x=πx = \pi, and x=2πx = 2\pi. More broadly, sin(x)\sin(x) is zero at every integer multiple of π\pi. Thus, the solutions to the equation sin(x)=0\sin(x) = 0 can be expressed as x=nπx = n\pi, where nn can be any integer (including positive, negative, or zero). This notation encompasses the values such as ,2π,π,0,π,2π,3π\ldots, -2\pi, -\pi, 0, \pi, 2\pi, 3\pi, and so on.

To grasp why this occurs, consider the unit circle. On this circle, the sine of an angle corresponds to the y-coordinate of the point that represents that angle. The y-coordinate is zero at the points (1,0)(1, 0) and (1,0)(-1, 0), which correspond to the angles 00, π\pi, 2π2\pi, and so on. These points recur every π\pi radians, leading us to the general solution x=nπx = n\pi.

In conclusion, the equation sin(x)=0\sin(x) = 0 has an infinite number of solutions, all of which are integer multiples of π\pi. Recognizing this pattern is essential for understanding the behavior of trigonometric functions and for solving more complex trigonometric equations.

Answered by: Prof. Richard White
A-Level Maths Tutor
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