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How do you find the space diagonal of a cube with edge length 4 cm?

The space diagonal of a cube with an edge length of 4cm4 \, \text{cm} is given by 43cm4\sqrt{3} \, \text{cm}.

To determine the space diagonal of a cube, we can use the formula:

d=a3d = a\sqrt{3}

where dd represents the space diagonal and aa is the edge length of the cube. For our example, the edge length aa is 4cm4 \, \text{cm}. Substituting this value into the formula yields:

d=43cm.d = 4\sqrt{3} \, \text{cm}.

Let’s explore the reasoning behind this formula. A cube has three dimensions: length, width, and height, all of which are equal. The space diagonal is the longest diagonal that stretches from one vertex of the cube to the opposite vertex, traversing through the interior of the cube. To derive the space diagonal, we can apply the Pythagorean theorem in three dimensions.

First, we calculate the diagonal of one face of the cube. Since each face is a square with an edge length of 4cm4 \, \text{cm}, we can use the Pythagorean theorem in two dimensions to find the face diagonal:

diagonal=42+42=16+16=32=42cm.\text{diagonal} = \sqrt{4^2 + 4^2} = \sqrt{16 + 16} = \sqrt{32} = 4\sqrt{2} \, \text{cm}.

Next, we consider this face diagonal as one leg of a right triangle, with the other leg being the edge of the cube, which is also 4cm4 \, \text{cm}. Using the Pythagorean theorem again in three dimensions, we can determine the space diagonal dd:

d=(42)2+42=16×2+16=32+16=48=43cm.d = \sqrt{(4\sqrt{2})^2 + 4^2} = \sqrt{16 \times 2 + 16} = \sqrt{32 + 16} = \sqrt{48} = 4\sqrt{3} \, \text{cm}.

Thus, we confirm that the space diagonal of a cube with an edge length of 4cm4 \, \text{cm} is indeed 43cm4\sqrt{3} \, \text{cm}.

Answered by: Dr. Angela Davis
GCSE Maths Tutor
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