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How do you find the length of a diagonal in a cuboid using Pythagoras' Theorem?

To calculate the length of a diagonal in a cuboid, you can use the formula:

d=l2+w2+h2d = \sqrt{l^2 + w^2 + h^2}

where ll represents the length, ww the width, and hh the height of the cuboid. A cuboid is a three-dimensional shape defined by these three dimensions.

To determine the diagonal that extends from one corner of the cuboid to the opposite corner, we can apply Pythagoras’ Theorem in three dimensions.

First, consider the diagonal of the base of the cuboid. If you look at the rectangular base with length ll and width ww, the diagonal d1d_1 of this rectangle can be calculated using Pythagoras’ Theorem:

d1=l2+w2d_1 = \sqrt{l^2 + w^2}

This calculation is valid because the diagonal forms a right-angled triangle with the length and width of the rectangle.

Next, envision this diagonal d1d_1 as the base of another right-angled triangle, where the height hh of the cuboid serves as the other perpendicular side. To find the length of the space diagonal dd of the cuboid, we apply Pythagoras’ Theorem once more, this time in three dimensions. The formula is:

d=d12+h2d = \sqrt{d_1^2 + h^2}

By substituting d1d_1 with l2+w2\sqrt{l^2 + w^2}, we arrive at:

d=(l2+w2)2+h2d = \sqrt{(\sqrt{l^2 + w^2})^2 + h^2}

This simplifies to:

d=l2+w2+h2d = \sqrt{l^2 + w^2 + h^2}

In summary, by applying Pythagoras’ Theorem twice, you can find the length of the diagonal in a cuboid using the formula:

d=l2+w2+h2d = \sqrt{l^2 + w^2 + h^2}

This approach illustrates the relationship between the cuboid’s dimensions and the length of its diagonal.

Answered by: Dr. Emily Clark
GCSE Maths Tutor
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