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How do you find the exact value of $\cos 60^\circ$?

The exact value of cos60\cos 60^\circ is 12\frac{1}{2}.

To grasp why cos60\cos 60^\circ equals 12\frac{1}{2}, we can explore the properties of special triangles, notably the 30-60-90 triangle. This particular triangle is a right-angled triangle with angles measuring 3030^\circ, 6060^\circ, and 9090^\circ. The sides of a 30-60-90 triangle have a specific ratio: the side opposite the 3030^\circ angle is the shortest and is half the length of the hypotenuse. The side opposite the 6060^\circ angle measures 3\sqrt{3} times the shortest side, while the hypotenuse is the longest side.

Let us consider a 30-60-90 triangle where the shortest side (opposite the 3030^\circ angle) is set to 11 unit. Consequently, the hypotenuse will be 22 units, as it is twice the length of the shortest side. The side opposite the 6060^\circ angle will then measure 3\sqrt{3} units.

The cosine of an angle in a right triangle is defined as the length of the adjacent side divided by the length of the hypotenuse. For the 6060^\circ angle in our 30-60-90 triangle, the adjacent side corresponds to the shortest side, which is 11 unit, and the hypotenuse is 22 units. Therefore, we can express this as:

cos60=adjacenthypotenuse=12.\cos 60^\circ = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{1}{2}.

This relationship is consistent across all 30-60-90 triangles, as the ratios between their sides remain unchanged. Thus, we can confidently state that the exact value of cos60\cos 60^\circ is always 12\frac{1}{2}.

Answered by: Prof. Michael Lewis
IB Physics Tutor
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