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How do you find the area of a triangle with two sides and an included angle?

To determine the area of a triangle when you know the lengths of two sides and the included angle, you can use the formula:

Area=12absin(C)\text{Area} = \frac{1}{2}ab\sin(C)

where aa and bb are the lengths of the two sides, and CC is the measure of the included angle.

This formula is particularly advantageous when you do not have the height of the triangle but do have the lengths of two sides and the angle formed between them. Here’s a step-by-step guide on how to apply this formula:

  1. Identify the lengths of the two sides, denoted as aa and bb.
  2. Measure or determine the included angle CC in either degrees or radians.
  3. Use a scientific calculator to compute sin(C)\sin(C). Ensure that your calculator is set to the correct mode: degrees if CC is in degrees, and radians if CC is in radians.
  4. Multiply the lengths of the two sides: a×ba \times b.
  5. Multiply this result by the sine of the included angle: a×b×sin(C)a \times b \times \sin(C).
  6. Finally, multiply by 12\frac{1}{2} to obtain the area:
Area=12absin(C).\text{Area} = \frac{1}{2}ab\sin(C).

Example Calculation

Consider a triangle with sides a=5a = 5 cm, b=7b = 7 cm, and the included angle C=60C = 60^\circ. The area can be calculated as follows:

  1. Calculate sin(60)\sin(60^\circ):
sin(60)=320.866.\sin(60^\circ) = \frac{\sqrt{3}}{2} \approx 0.866.
  1. Multiply the lengths of the sides:
5×7=35.5 \times 7 = 35.
  1. Multiply this result by sin(60)\sin(60^\circ):
35×0.86630.31.35 \times 0.866 \approx 30.31.
  1. Finally, multiply by 12\frac{1}{2}:
12×30.3115.16 cm2.\frac{1}{2} \times 30.31 \approx 15.16 \text{ cm}^2.

Thus, the area of the triangle is approximately 15.16cm215.16 \, \text{cm}^2.

Answered by: Dr. Emily Clark
GCSE Maths Tutor
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