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How do you determine the maximum value of y = sin(x)?

The maximum value of the function y=sin(x)y = \sin(x) is 11.

To comprehend why the highest value of y=sin(x)y = \sin(x) is 11, it is essential to examine the characteristics of the sine function. The sine function is periodic, meaning it exhibits a repeating pattern at regular intervals. Specifically, it has a period of 360360^\circ (or 2π2\pi radians), indicating that the function’s values repeat every 360360^\circ.

The sine function oscillates between 1-1 and 11. Consequently, for any angle xx, the value of sin(x)\sin(x) will always fall within this range. The maximum point on the sine curve is 11, which occurs at specific angles within each period. For instance, sin(90)=1\sin(90^\circ) = 1 and sin(450)=1\sin(450^\circ) = 1. In radian measure, this translates to sin(π2)=1\sin\left(\frac{\pi}{2}\right) = 1 and sin(5π2)=1\sin\left(\frac{5\pi}{2}\right) = 1.

To visualize this behavior, consider sketching the graph of y=sin(x)y = \sin(x). The graph forms a smooth, wave-like curve, oscillating between 11 and 1-1. The points at which the curve reaches 11 correspond to the peaks of the wave. These peaks occur at regular intervals, specifically at:

x=90+360korx=π2+2πk,x = 90^\circ + 360^\circ k \quad \text{or} \quad x = \frac{\pi}{2} + 2\pi k,

where kk is any integer.

By understanding these properties, it becomes clear that the maximum value of the sine function is always 11, regardless of the angle xx. This characteristic is fundamental to the sine function and plays a crucial role in solving various trigonometric problems in GCSE Mathematics.

Answered by: Dr. Angela Davis
GCSE Maths Tutor
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