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Find the roots of the quadratic equation 2x^2 - 3x - 5 = 0

To find the roots of the quadratic equation

2x23x5=0,2x^2 - 3x - 5 = 0,

we can utilize the quadratic formula, which is given by

x=b±b24ac2a.x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.

In this formula, the coefficients are defined as follows: a=2a = 2, b=3b = -3, and c=5c = -5. By substituting these values into the quadratic formula, we proceed as follows:

x=(3)±(3)24(2)(5)2(2).x = \frac{-(-3) \pm \sqrt{(-3)^2 - 4(2)(-5)}}{2(2)}.

This simplifies to:

x=3±9+404.x = \frac{3 \pm \sqrt{9 + 40}}{4}.

Continuing with the simplification, we have:

x=3±494.x = \frac{3 \pm \sqrt{49}}{4}.

Since the square root of 4949 is 77, we can further simplify to:

x=3+74orx=374.x = \frac{3 + 7}{4} \quad \text{or} \quad x = \frac{3 - 7}{4}.

Calculating these two expressions yields:

x=104=52andx=44=1.x = \frac{10}{4} = \frac{5}{2} \quad \text{and} \quad x = \frac{-4}{4} = -1.

Thus, the roots of the quadratic equation

2x23x5=02x^2 - 3x - 5 = 0

are

x=52andx=1.x = \frac{5}{2} \quad \text{and} \quad x = -1.

To verify our solutions, we can substitute these values back into the original equation to ensure they satisfy it.

Answered by: Prof. Peter Brown
IB Maths Tutor
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