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Explain the concept of relative displacement

Relative displacement refers to the change in position of one object in relation to another object. It is a vector quantity, meaning it has both magnitude and direction.

To calculate relative displacement, you subtract the initial position vector of the second object from the final position vector of the first object. This can be mathematically represented as:

Relative Displacement=rA,frB,i\text{Relative Displacement} = \mathbf{r}_{A,f} - \mathbf{r}_{B,i}

where rA,f\mathbf{r}_{A,f} is the final position vector of object A and rB,i\mathbf{r}_{B,i} is the initial position vector of object B.

For instance, consider the following example: If object A moves from position (2,3)(2,3) to position (5,7)(5,7) and object B moves from position (1,1)(1,1) to position (4,5)(4,5), the relative displacement of object A with respect to object B can be calculated as follows:

Relative Displacement=(5,7)(1,1)=(4,6)\text{Relative Displacement} = (5,7) - (1,1) = (4,6)

This result indicates that object A has moved 44 units to the right and 66 units upwards relative to object B.

It is important to note that relative displacement can be negative, which occurs when the two objects move in opposite directions. For example, if object A moves from position (2,3)(2,3) to position (5,7)(5,7) and object B moves from position (6,5)(6,5) to position (3,1)(3,1), the relative displacement of object A with respect to object B is:

Relative Displacement=(5,7)(6,5)=(1,2)\text{Relative Displacement} = (5,7) - (6,5) = (-1,2)

In this case, the negative value indicates that object A has moved 11 unit to the left and 22 units upwards in relation to object B.

Understanding relative displacement is crucial in physics and engineering, as it allows us to describe the motion of objects in relation to one another effectively.

Answered by: Dr. Michael Green
A-Level Maths Tutor
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