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Differentiate the function y = cot(4x)

Let’s enhance the clarity and readability of the content, ensuring proper formatting for mathematical expressions.


To find the derivative of the function y=cot(4x)y = \cot(4x), we will use the chain rule.

First, we can introduce a substitution to simplify our calculations. Let u=4xu = 4x. Consequently, we can rewrite our function as y=cot(u)y = \cot(u).

According to the chain rule, the derivative of yy with respect to xx can be expressed as:

dydx=dydududx\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx}

Next, we need to compute dydu\frac{dy}{du}. The derivative of cot(u)\cot(u) is given by:

dydu=csc2(u)\frac{dy}{du} = -\csc^2(u)

Substituting back for uu, we have:

dydu=csc2(4x)\frac{dy}{du} = -\csc^2(4x)

Now, we determine dudx\frac{du}{dx}. The derivative of uu with respect to xx is:

dudx=4\frac{du}{dx} = 4

We can now substitute both derivatives back into our chain rule expression:

dydx=csc2(4x)4\frac{dy}{dx} = -\csc^2(4x) \cdot 4

Simplifying this expression, we obtain:

dydx=4csc2(4x)\frac{dy}{dx} = -4 \csc^2(4x)

Thus, we conclude that the derivative of y=cot(4x)y = \cot(4x) is:

dydx=4csc2(4x)\frac{dy}{dx} = -4 \csc^2(4x)

This presentation enhances clarity and maintains proper formatting for mathematical expressions while slightly rephrasing the content for improved readability.

Answered by: Dr. Lucas Harris
A-Level Maths Tutor
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